Using b1=b:
logbb=1
Using b0=1:
logb1=0
Let:
logax=m(9.1)
logay=n(9.2)
In exponential form:
x=am(9.3)
y=an(9.4)
Multiplying (9.3) by (9.4):
xy=am⋅an
xy=am+n(9.5)
In logarithmic form:
loga(xy)=m+n
loga(xy)=logax+logay
Dividing (9.3) by (9.4):
yx=anam
yx=am−n
loga(yx)=logaam−n
loga(yx)=(m−n)
loga(yx)=logax−logay
Using x=am (so logax=m) and raising both sides to the power of n:
xn=(am)n
xn=amn
logaxn=mn
logaxn=nlogax