An arithmetic progression is a sequence of numbers where each term increases or decreases by a constant amount called the common difference (d). The first term is denoted by a.
General Term of an AP
The general (nth) term of an AP is given by:
an=a+(n−1)d
This formula works because:
- First term: a₁ = a + (1 - 1)d = a
- Second term: a₂ = a + (2 - 1)d = a + d
- Third term: a₃ = a + (3 - 1)d = a + 2d
- And so on...
Deriving the Sum Formula for an AP
To find the sum of the first n terms (Sₙ), write the series forwards and backwards, then add them:
Sn=a+(a+d)+(a+2d)+...+[a+(n−1)d]
Write it in reverse:
Sn=[a+(n−1)d]+[a+(n−2)d]+...+a
Adding both expressions term by term:
2Sn=[a+a+(n−1)d]+[a+d+a+(n−2)d]+...+[a+(n−1)d+a]
Each pair sums to: 2a + (n - 1)d
There are n such pairs, therefore:
2Sn=n[2a+(n−1)d]
Sn=2n[2a+(n−1)d]
This is the sum formula for an Arithmetic Progression.
Worked Example
Find the sum of the first 20 terms of the AP: 5, 8, 11, 14, ...
Solution:
Given: first term a = 5, common difference d = 8 - 5 = 3, number of terms n = 20
Using the sum formula:
S20=220[2(5)+(20−1)(3)]
S20=10[10+19×3]
S20=10[10+57]
S20=10×67=670
Therefore, the sum of the first 20 terms is 670.