A student standing at point A on the ground observes the top of a radio tower at point C. The angle of elevation to the top of the tower is 35°. The student then walks 50 meters directly away from the tower to point B. From point B, the angle of elevation to the top of the tower is 20°. Find the height of the tower (point C to the ground).
Solution
Step 1: Draw a diagram and identify the triangle
Let:
- h = height of the tower (in meters)
- AB = 50 m (distance the student walked)
- Let the distance from A to the base of the tower be x meters
Then from point B, the distance to the base of the tower is (x + 50) meters.
Step 2: Set up equations using tangent
In triangle ACD (from point A):
tan35°=xh
So: h=xtan35° ...(1)
In triangle BCD (from point B):
tan20°=x+50h
So: h=(x+50)tan20° ...(2)
Step 3: Equate the two expressions for h
xtan35°=(x+50)tan20°
xtan35°=xtan20°+50tan20°
x(tan35°−tan20°)=50tan20°
x=tan35°−tan20°50tan20°
Calculating values:
- tan 20° ≈ 0.3640
- tan 35° ≈ 0.7002
x=0.7002−0.364050×0.3640=0.336218.2≈54.1 m
Step 4: Find the height of the tower
From equation (1):
h=xtan35°=54.1×0.7002≈37.9 m
Therefore, the height of the radio tower is approximately 38 meters.