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Advanced Mathematics 1

Introduction to Partial Derivatives

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Mada za sehemu hiiDifferentiationMada 5

Introduction to partial derivatives

A function z=f(x,y)z = f(x, y) depends on two independent variables, xx and yy. A partial derivative measures how the function changes with respect to one variable, while holding the other constant.

Notation

  1. zx\frac{\partial z}{\partial x} or fxf_x represents the partial derivative of zz with respect to xx (holding yy constant).
  2. zy\frac{\partial z}{\partial y} or fyf_y represents the partial derivative of zz with respect to yy (holding xx constant).
  3. Second partial derivatives:
    • 2zx2\frac{\partial^2 z}{\partial x^2} or fxxf_{xx} (derivative with respect to xx twice)
    • 2zy2\frac{\partial^2 z}{\partial y^2} or fyyf_{yy} (derivative with respect to yy twice)
    • 2zxy\frac{\partial^2 z}{\partial x \partial y} or fxyf_{xy} (derivative first with respect to yy, then xx)
    • 2zyx\frac{\partial^2 z}{\partial y \partial x} or fyxf_{yx} (derivative first with respect to xx, then yy)

Definition

The partial derivative of z=f(x,y)z = f(x, y) with respect to xx is defined as:

zx=limh0f(x+h,y)f(x,y)h\frac{\partial z}{\partial x} = \lim_{h \to 0} \frac{f(x + h, y) - f(x, y)}{h}

The partial derivative of z=f(x,y)z = f(x, y) with respect to yy is defined as:

zy=limh0f(x,y+h)f(x,y)h\frac{\partial z}{\partial y} = \lim_{h \to 0} \frac{f(x, y + h) - f(x, y)}{h}

Example 1: Find the first partial derivatives of z=x2+xy+y3z = x^2 + xy + y^3.

To find zx\frac{\partial z}{\partial x}, treat yy as a constant:

zx=2x+y\frac{\partial z}{\partial x} = 2x + y

To find zy\frac{\partial z}{\partial y}, treat xx as a constant:

zy=x+3y2\frac{\partial z}{\partial y} = x + 3y^2

Example 2: Find the first partial derivatives of z=sin(3x)cos(4y)z = \sin(3x) \cos(4y).

To find zx\frac{\partial z}{\partial x}, treat yy as a constant:

zx=3cos(3x)cos(4y)\frac{\partial z}{\partial x} = 3\cos(3x) \cos(4y)

To find zy\frac{\partial z}{\partial y}, treat xx as a constant:

zy=4sin(3x)sin(4y)\frac{\partial z}{\partial y} = -4\sin(3x) \sin(4y)

Example 3: Find 2zx2\frac{\partial^2 z}{\partial x^2} if z=e3x+2yz = e^{3x + 2y}.

First, find zx\frac{\partial z}{\partial x}:

zx=3e3x+2y\frac{\partial z}{\partial x} = 3e^{3x + 2y}

Now, differentiate with respect to xx again:

2zx2=9e3x+2y\frac{\partial^2 z}{\partial x^2} = 9e^{3x + 2y}

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