Problem:
Find the horizontal and vertical components of a force of 10 N acting at 30° to the vertical.
Since angle is with respect to the vertical:
Horizontal component
Fx=Fsinθ
Vertical component
Fy=Fcosθ
Solution:
Given:
F=10N, θ=30∘
Step 1: Horizontal component
Fx=Fsinθ=10sin30∘
Fx=10×0.5=5N
Step 2: Vertical component
Fy=Fcosθ=10cos30∘
Fy=10×0.866=8.66N
Answer:
- Horizontal Component = 5 N
- Vertical Component = 8.66 N