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Simple equations

takriban dakika 1 kusoma

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Mada za sehemu hiiAlgebraMada 5

Example 1

Find the value of p in the following equation: p+2=3p + 2 = 3.

Solution

To make p remain alone on the left-hand side of the equation, move +2 to the other side of the equation. It becomes −2.

That is:

p=32p = 3 - 2 p=1p = 1

Therefore, the value of p=1p = 1.

Alternatively, from p+2=3p + 2 = 3, subtract 2 from both sides:

p+22=32p + 2 - 2 = 3 - 2 p=1p = 1

Therefore, the value of p=1p = 1.

Example 2

Find the value of x in the following equation: x+8=4x + 8 = 4.

Solution

x+8=4x + 8 = 4.

To make x remain alone on the left-hand side of the equation, subtract 8 from both sides:

x+88=48x + 8 - 8 = 4 - 8 x+0=4x + 0 = -4 x=4x = -4

Therefore, the value of x=4x = -4.

Example 3

Find the value of k in the following equation: 23+k=32-23 + k = 32.

Solution

23+k=32-23 + k = 32

Add 23 to both sides of the equation:

23+23+k=32+23-23 + 23 + k = 32 + 23 0+k=550 + k = 55 k=55k = 55

Therefore, the value of k=55k = 55.

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